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5xy42x - y = -1Solve system of equations using substitution method.

User Redson
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Given the systems of equation


\begin{gathered} 5x-y=4 \\ 2x-y=-1 \end{gathered}

We want to solve it using the substitution method. The first step is to get one equation from the systems of equations and solve it in terms of x. I will choose the second equation in this case. We have


\begin{gathered} 2x-y=-1 \\ -y=-1-2x \\ y=1+2x \end{gathered}

Put this equation on the first equation present in the system of equations and solve for x. We have


\begin{gathered} 5x-(1+2x)=4 \\ 5x-1-2x=4 \\ 5x-2x=4+1 \\ 3x=5 \\ x=(5)/(3) \end{gathered}

Use this value of x and substitute it on one of the equations on the system of equations to solve for the value of y. In this case, I will be using equation 2. We have


\begin{gathered} y=1+2((5)/(3))_{} \\ y=1+(10)/(3) \\ y=(3+10)/(3) \\ y=(13)/(3) \end{gathered}

User Djnz
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