Question

Bailey works part-time at a movie theater. The theater pays employees an hourly wage based on their length of employment. Write an algebraic expression that describes how much Bailey's employer pays part-time workers pay increase per 6 months period is:pay increase per month is:show work:algebraic expression that describes pay per month:

Answer 1

Given the following question:

To find the answer we will need to write it in slope intercept form:

`\begin{gathered} m=(y2-y1)/(x2-x1) \\ m=(7.85-7.55)/(12-6)=(0.30)/(6) \\ (0.30)/(6)=0.05 \\ y=mx+b \\ x=6 \\ y=7.55 \\ m=0.05 \\ 7.55=0.05(6)+b \\ \text{Solve for b} \\ 0.05*6=0.3 \\ 7.55=0.3+b \\ 0.3-0.3=0 \\ 7.55-0.3=7.25 \\ b=7.25 \\ y=0.05x+7.25 \\ \text{ the equation required to solve} \end{gathered}`

Every 6 months the employees have a $0.30 increase in pay

`\begin{gathered} 0.30/6=0.05 \\ \end{gathered}`

Pay increase per month is 0.05