Question

How do you solve quadratic using square roots?ex: 1/5x²+2=3/5x²

Answer 1

`\begin{gathered} (1)/(5)x^2+2=(3)/(5)x^2​ \\ 2=(3)/(5)x^2​-(1)/(5)x^2(\text{Subtracting }(1)/(5)x^2\text{ on both sides of the equation)} \\ 2=\text{ }(2)/(5)x^2\text{ (Subtracting)} \\ 2\cdot5=\text{ 2}x^2\text{ (Multiplying by 5 on both sides of the equation)} \\ 10/2=\text{ }x^2\text{ (Dividing by 2 on both sides of the equation)} \\ 5=x^2\text{ (Dividing)} \\ \pm\sqrt[]{5}=x\text{ (Taking the square root on both sides of the equation)} \\ \text{The solutions are x=}\sqrt[]{5}\text{ and x=}-\sqrt[]{5}\text{ } \end{gathered}`