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Jade and Alberta are selling fruit.Customers can buy small boxes and large boxes of oranges.Jade sold 16 small boxes and 12 large boxes for a total of 344.00.Alberta sold 8 small boxes and 8 large boxes for a total of 208.00.what would the cost of one large and one small box cost?

User Tinonetic
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Assume that the cost of the small box is x and the large box is y

Since Jade sold 16 small boxes and 12 larger boxes for 344, then


16x+12y=344(1)

Since Alberts sold 8 small boxes and 8 larger boxes for 208, then


8x+8y=208(2)

Now, we have a system of equations to solve it

Multiply equation (2) by -2


\begin{gathered} -2(8x)+(-2)(8y)=-2(208) \\ -16x-16y=-416(3) \end{gathered}

Add equations (1) and (3) to eliminate x


\begin{gathered} (16x-16x)+(12y-16y)=(344-416) \\ -4y=-72 \end{gathered}

Divide both sides by -4


\begin{gathered} (-4y)/(-4)=(-72)/(-4) \\ y=18 \end{gathered}

Substitute the value of y in equation

User Bob Gilmore
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