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How long does it take for an investment to double in value if it is invested at 2% compounded quarterly? Compounded continuously?At 2% compounded quarterly, the investment doubles in about(Round to two decimal places as needed)years

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The SOLUTION

Recall the formula for compound interest formula


A=P(1+(r)/(n))^(nt)

For the amount to double then A=2P

From the question it follows:


\begin{gathered} r=2\%=0.02 \\ n=4 \end{gathered}

Substituting these values gives:


2P=P(1+(0.02)/(4))^(4t)

Solve for t


\begin{gathered} 2=1.005^(4t) \\ \Rightarrow t\approx34.74 \end{gathered}

Therefore the number of years it will take for the amount to double is 34.74 years

Using the compounded continuously formula

Substituting values gives


2P=Pe^(0.02t)

Solve for t


\begin{gathered} 2=e^(0.02t) \\ \Rightarrow t\approx34.66 \end{gathered}

For compounded continuously, the investment will double in about 34.66 years

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