Question

Sissy wants to enlarge a picture of a constellation so that she can put it on the wall in her daughter’s room. What will be the area of the enlarged picture on the wall? 24 in.2108 in.2224 in.2486 in.2

Answer 1

Answer: 486 in. ^2

Step-by-step explanation: I just did the assignment on edge! :)

Answer 2

We have the given parameters

The dimensions of the small rectangle are

To get the dimension of the big rectangle, we will use the scale factor:

`\frac{Dis\tan ce\text{ of big rectangle from Q}}{Dis\tan ce\text{ of small rectangle from Q}}=(QL^(\prime))/(QL)`

From the image given

`(QL^(\prime))/(QL)=(12+42)/(12)=(54)/(12)=4.5`

To get the dimensions of the big rectangle, we will simply multiply the sides of the small rectangle by the scale factor, so that we will obtain

Since we have gotten the dimensions of the big rectangle, we can now compute the area

`\begin{gathered} \text{Area of rectangle=length}* breadth=27*18=486in^2 \\ \end{gathered}`

Thus, the answer is option D

`486\text{ in}^2`