Question

Find the value of x in the triangle shown below.

Answer 1

`\huge\boxed{\sf P =√(45) }`

Explanation:

Since, the triangle is a right angled triangle, we can use Pythagoras theorem to find the perpendicular of the triangle.

Which is:

`(Hypotenuse)^2=(Base)^2+(Perpendicular)^2`

Rearranging

(Perpendicular)² = (Hypotenuse)² - (Base)²

Where P = ?, H = 7 and B = 2

(P)² = (7)² - (2)²

(P)² = 49 - 4

(P)² = 45

Take sqrt on both sides

`P =√(45)`

`\rule[225]{225}{2}`

Hope this helped!

~AH1807