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What is the y-intercept of the graph of y = 0.5(x - 2)^2 + c, where c is a constant?

User Giorgina
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1 Answer

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We are given the equation :


y=0.5(x-2)^2\text{ + c}

The y-intercept of the graph is the value of y when x = 0.

When x = 0,


\begin{gathered} y=0.5(0-2)^2\text{ + c} \\ y\text{ = }0.5(-2)^2\text{ + c} \\ y\text{ = 0.5 }*\text{ 4 + c} \\ y\text{ = 2 + c} \end{gathered}

Hence the y-intercept of the graph/equation is 2 + c, where c is a constant

Answer: 2 + c

User Effel
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