Question

2(z-1)+3(z-1)=4+2z (find z)i dont really know how to solve this

Answer 1

`z=3`

Step-by-step explanation

We want to solve the given equation for z:

`2(z-1)+3(z-1)=4+2z`

First, expand the brackets:

`\begin{gathered} (2*z)-(2*1)+(3*z)-(3*1)=4+2z \\ \\ 2z-2+3z-3=4+2z \end{gathered}`

Next, collect like terms by putting all the algebraic terms (terms with z) on the left and the integers on the right:

`2z+3z-2z=4+3+2`

Now, simplify and solve for z:

`\begin{gathered} 3z=9 \\ \\ (3z)/(3)=(9)/(3) \\ \\ z=3 \end{gathered}`

That is the value of z.