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F(x) = (x-1.5)^2 find the vertex

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The given function is


f(x)=(x-1.5)^2

It is important to know that the function is in vertex form


f(x)=a(x-h)^2+k

Where h and k are the coordinates of the vertex.

Having said that, we can deduct that the vertex of the given function is (1.5, 0) because those are the values for h and k.

Hence, the answer is V(1.5, 0).

User Dan Patil
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