the equation of vertex: (5,4) focus: (5,8).
Since the x coordinates of vertex and focus are same, the focus and the vertex lies on the same vertical line, x=5. So, the parabla has vertical symmetry. The focus is above vertex as seen from the coordinates. So, the parabola opens upwards.
a=8-4=4.
The equation for vertical parabola is,
![\begin{gathered} (x-h)^2=4a(y-k) \\ \text{Here, (h,k ) is vertex.} \\ (h,k)=(5,4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/om13ghqudw2uouvefo8bs1urubpvejgvsg.png)
So, the equation of parabola can be obtained as,
![\begin{gathered} (x-5)^2=4*4(y-4) \\ (x-5)^2=16(y-4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/c4idz7qs2jwo7l8qserwf27gsfq3ljnj3j.png)
Therefore, the equation of parabola is
![(x-5)^2=16(y-4)](https://img.qammunity.org/2023/formulas/mathematics/college/2qptq704fffhp3qhiuevri4kn09arnxeyx.png)