Answer and Explanation:
Using trig ratios, we can express the given values of sin u and tan v as shown below
![\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=(2)/(5) \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xg172k9lplshpgddec4btb3lf87fckaapc.png)
So we can go ahead and label the sides of the triangle as shown below;
We can find the value of u as shown below;

We can find v as shown below;
