Question

Find the center of mass of the following 3-object system:1.00 kg1.50 kg1.10 kg0.50 m+0.25 mm from the left.

Answer 1

0.4375 m

Explanation:

Given:

Masses and positions of 3 objects are:

m1 = 1 kg located x1 = 0 m

m2 = 1.5 kg located x2 = 0.5 m

m3= 1.1kg located x3 = 0.5 + 0.25 = 0.75 m

Therefore, the center of mass of system is:

`\begin{gathered} x_(cm)=(m_1\cdot x_1+m_2\cdot x_2+m_3\cdot x_3)/(m_1+m_2+m_3) \\ \\ \text{ We replacing:} \\ \\ x_(cm)=(1\cdot0+1.5\cdot0.5+1.1\cdot0.75)/(1+1.5+1.1) \\ \\ x_(cm)=(1.575)/(3.6) \\ \\ x_(cm)=0.4375\text{ m} \end{gathered}`

Therefore, the center of mass is 0.4375 meters from the left.