Question

Hello,Can you help me find the height of the arrow

Answer 1

given :

`\begin{gathered} h(x)=-16t^2+96t \\ \end{gathered}`

the parabola opens downwards. thus the maximum point is the vertex.

`\begin{gathered} t(v)=-(b)/(2a) \\ =(-96)/(-32) \\ =3\sec \end{gathered}`

thus,

`\begin{gathered} h(3)=-16(3)^2+96*3 \\ =-144+288 \\ =144ft \end{gathered}`

the answer is 144ft.