The probability (P) an Event A or an Event B occurs is P(A) + P(B).
The probability of an event A occuring is:
![P(A)=\frac{\text{ number of favorable outcomes of A}}{\text{ total number of outcomes}}](https://img.qammunity.org/2023/formulas/mathematics/college/vzjsusxhx59p02kntml7bjvehj7rp70wx0.png)
When rolling two dices, the sum can be:
If the result of the first dice is 1:
2, 3, 4, 5, 6, 7
If the result of the first dice is 2:
3, 4, 5, 6, 7, 8
If the result of the first dice is 3:
4, 5, 6, 7, 8, 9
If the result of the first dice is 4:
5, 6, 7, 8, 9, 10
If the result of the first dice is 5:
6, 7, 8, 9, 10, 11
If the result of the first dice is 6:
7, 8, 9, 10, 11, 12
Thus, there are 36 possible combinations.
From these combinations,
15 sums are less than 7
3 sums are greater than 10
Then, the probability of event A (sum is less than 7) is:
![P(A)=(15)/(36)=(5)/(12)](https://img.qammunity.org/2023/formulas/mathematics/college/8qqn3soizeuedrb99sanaeojhs6e8ytqd2.png)
And the probability that event B (sum is greater than 10) occurs:
![P(B)=(3)/(36)=(1)/(12)](https://img.qammunity.org/2023/formulas/mathematics/college/xdggp4xauzgz6bor2mvci4uynpia2xieid.png)
Finally:
![\begin{gathered} P(A+B)=(15)/(36)+(3)/(36)=(18)/(36) \\ P(A+B)=(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/b10v4p4caybbc8r6cvnhdre3vpx8diaq7q.png)
Answer: 1/2.