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I been trying to answer this all day but I need some help

I been trying to answer this all day but I need some help-example-1

1 Answer

7 votes

1. The area of a 7 inch pizza

A = pi r^2

We need the radius

r = d/2 = 7/2 = 3.5 inches

A = 3.14 ( 3.5)^2 = 38.465 in ^2 = 38.5 in^2

The area of a 11 inch pizza

A = pi r^2

We need the radius

r = d/2 = 11/2 = 5.5 inches

A = 3.14 ( 5.5)^2 = 94.985 in ^2 = 95.0 in^2

2. The total area of the pizzas is found by adding the areas together

2* 38.5+95.0 = 77+95=172 in ^2

3. 2 7 inches pizzas is 77 inches^2 while 11 inches pizza is 95 in^2 so you get more pizza with the 11 inch pizza

4. We can use ratios to determine the cost for 2 7 inch pizzas

95 inches ^2 77 inches ^2

---------------------- = --------------

9.99 cost

Using cross products

95 * cost = 9.99 *77

95 * cost = 769.23

cost = 769.23/95

cost = 8.10

The two pizzas should cost 8.10 to be the same value

5. Compare 1 7 inch pizza to 1 11inch pizza

95 inches^2 - 38.5 inches^2 = 56.5 inches ^2 difference

6. Take the area that is more ( 56.5) and divide by the area of the 7 inch to get the percent more

56.5 / 38.5 = 1.467532

Change to percent form

146.7532 %

7. Take the area of 1 7 inch pizza 38.5 inches ^2 and divide by 4

38.5 /4 =9.625 inches ^2

Multiply by 3 for 3 slices

3 * 9.625 =28.875 inches ^2

8. 5 slices of an 8 slice pizza is 5/8 = .625 = 62.5 %

Multiply .625 by the area of the pizza

.625 * 95 =59.375 inches ^2

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