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Subtract. please help
\frac{1}{3 {x}^(2) } - \frac{x}{ {x}^(2) - 8}

User Sheryll
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1 Answer

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Solution


(1)/(3x^2)-(x)/(x^2-8)

Find the LCM and subtarct the numerator


\text{LCM }=3x^2(x^2-8)\text{ }


\begin{gathered} =(\left(x+2√(2)\right)\left(x-2√(2)\right))/(3x^2\left(x+2√(2)\right)\left(x-2√(2)\right))-(3x^3)/(3x^2\left(x+2√(2)\right)\left(x-2√(2)\right)) \\ \mathrm{Apply\: the\: fraction\: rule}\colon\quad (a)/(c)-(b)/(c)=(a-b)/(c) \end{gathered}
\begin{gathered} =(\left(x+2√(2)\right)\left(x-2√(2)\right)-3x^3)/(3x^2\left(x+2√(2)\right)\left(x-2√(2)\right)) \\ =(x^2-8-3x^3)/(3x^2\left(x+2√(2)\right)\left(x-2√(2)\right)) \end{gathered}
\begin{gathered} Expand(x+2\sqrt[]{2)}(x-2\sqrt[]{2)} \\ =(x^2-8-3x^3)/(3x^2\left(x^2-8\right)) \end{gathered}

User Weisheng Wu
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