Question

19. Two charges (Q1=-1.7x10°C and Q2= 4.4x10-6C) are separated by 0.03m. What isthe electric force between them?I

Answer 1

Apply Coulomb's Law:

`Fc=(kq1q2)/(r^(^2))`

Where:

F = Electric Force [N]

k = Coulomb constant = 9 x 10 ^9 Nm^2 / C^2

q1 = charge 1 = -1.7x10^-9^ C

q2= charge 2 = 4.4x10^^-6

r = distance = 0.03 m

Replacing:

`Fc=((9x10^9)(-1.7x10^(-9))(4.4x10^(-6)))/((0.03)^2)`

Fc = -0.0748 N

C