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What is the molarity of the solution produced when 152 g of ammonia is dissolved in sufficient water to prepare 2.75 L of solution?

User Dan Blows
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1 Answer

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Step 1

A solution is made up of a solute and a solvent

Solute = ammonia = NH3

Solvent = water = H2O

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Step 2

Information provided:

The mass of NH3 = 152 g

The volume of the solution = 2.75 L

Information needed:

The molar mass of NH3 = 17.0 g/mol

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Step 3

Molarity (mol/L or M) = moles of NH3/volume of the solution (L)

Moles of NH3 = mass of NH3/molar mass NH3 = 152 g/17.0 g/mol = 8.94 moles

Therefore, Molarity = 8.94 moles/2.75 L = 3.25 mol/L

Answer: Molarity = 3.25 mol/L

User Chew Socks
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