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The length of a rectangle is 2 inches less than 4 times the width. The perimeter is 86 inches. Find the length and the width.The length is ? inches and the width is ? inches.

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The perimeter of a rectangle is given by


p=2l+2w

Where

p - perimeter

l - length

w - width

We know that the length is 2 inches less than 4 times the width, then


l=4w-2

We also know that the perimeter is 86 inches, then


86=2l+2w

Now we have two equations:


\begin{cases}l=4w-2 \\ 86=2l+2w\end{cases}

Let's just rewrite the equations


\begin{cases}l-4w=-2 \\ 2l+2w=86\end{cases}

Now we have a system of equations, let's multiple the first equation by -2


\begin{cases}-2l+8w=4 \\ 2l+2w=86\end{cases}

Now we sum the equations


\begin{gathered} -2l+2l+8w+2w=86+4 \\ \\ 10w=90 \\ \\ w=9\text{ inches} \end{gathered}

Now we already know that the width is 9 inches. We can find the length using the equation:


\begin{gathered} l=4w-2 \\ \\ l=4\cdot9-2 \\ \\ l=34\text{ inches} \end{gathered}

The length is 34 inches and the width is 9 inches.

User Muhammad Hassaan
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