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How many solutions will each equation have?x^2+4x+4
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How many solutions will each equation have?x^2+4x+4

User Pgrenholm
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1 Answer

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To solve this quadratic equation, factor the expression and find the values of x


\begin{gathered} x^2+4x+4=0 \\ (x+2)(x+2)=0 \\ (x+2)^2=0 \\ x+2=0 \\ x=-2 \end{gathered}

In this case, there is only one solution for the equation, which is -2.

User MStodd
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