Given data
*The given mass of the student is m = 76 kg
*The given distance is s = 15 m
*The given time is t = 20 s
The speed of the student is calculated as
![\begin{gathered} v=(s)/(t) \\ =(15)/(20) \\ =0.75\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/vu7hyih62n854jrl2c344iwywgot9rb044.png)
The formula for the momentum of the student is given as
![p=mv](https://img.qammunity.org/2023/formulas/physics/college/zi8qkzyprj0sdsbzw2e0q1luo4qmume13x.png)
Substitute the known values in the above expression as
![\begin{gathered} p=(76)(0.75) \\ =57\text{ kg.m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/w1mn9l4ye1cgf1klr6d759jip8znmamwyu.png)
Hence, the momentum of the student is p = 57 kg.m/s