What is the exact value of sin(csc^-1 (2)), when 0° < A < 180°

asked Jul 1, 2023 227k views

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We have the expression:

$\sin (\csc ^(-1)(2))$

$0When we operate the function, we will get:[tex]\sin (\csc ^(-1)(2))=(1)/(2)$

That is, since:

$\csc ^(-1)(2)=(\pi)/(6)$

and then:

$\sin ((\pi)/(6))=(1)/(2)$

AntonioHS answered Jul 6, 2023

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