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Write the slope-intercept form of the equation of the line described. 7.) through: ( 2 , 3 ) , perpendicular to Y= -1/4x + 3

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point (2, 3)

y = -1/4x + 3

from equation y = mx + c

where m is the slope

slope = -1/4

since it is perpendicular to the point

m1 x m2 = -1

m2 = -1/m1

m1 = -1/4

m2 = -1 divided by -1/4

m2 = -1 x -4/1

m2 = -1 x -4

m2 = 4

the new equation will now be

(y - y1) = m(x - x1)

y1 = 3 and x1 = 2

y - 3 = 4(x - 2)

y - 3 = 4 *x - 4*2

y -3 = 4x -8

y = 4x -8 + 3

y = 4x -5

The slope - intercept form of the equation is y = 4x - 5

User Zignd
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