Question

The activity of 14C in a 50 -kg human body is estimated to be 2.6 kBq . What is this activity in microcuries?

Answer 1

To make the conversion we must take into account the relationship between kBq and microcuries. Both are units that represent radioactivity activity. The relationship is:

1 kilobecquerel (kBq) = 0.027027027 microcurie

Therefore, 2.6kBq will be equal to:

`\begin{gathered} microcuries=givenkBq*(0.027027027microcurie)/(1kBq) \\ m\imaginaryI crocur\imaginaryI es=2.6kBq*(0.027027027m\imaginaryI crocur\imaginaryI e)/(1kBq) \\ microcuries=0.070 \end{gathered}`

Answer= That activity in microcuries will be 0.070 microcuries