Answer:
0%
Step-by-step explanation:
Parents: Carrier woman x Hemophilic man
Genotype: XᴴXʰ x XʰY
Cross:
![\left[\begin{array}{ccc}&XH&Xh\\Xh&XHXh&XhXh\\Y&XHY&XhY\end{array}\right]](https://img.qammunity.org/2023/formulas/biology/college/mcdcsuqviu5metbsqo7zxglj1qadzu1ogf.png)
Result:
50% daughters are carrier, 50% daughters are hemophilic, 50% sons are normal, and 50% sons are hemophilic.
Conclusion:
When a heterozygous woman (a carrier) for the trait marries a man with hemophilia, the probability of the couple having a normal (non-carrier) daughter is 0%.