Question

5. A chemist needs to mix a 12% acid solution with a 32% acid solution to

obtain an 8-liters mixture consisting of 20% acid. How many liters of each of
the acid solutions must be used?

Answer 1

Let x = amount of 12% solution

Then, 8-x = amount of 32% solution

0.12x + 0.32(8-x) = 0.20(8)

=> x = 4.8