Question

I start with 298 K and a volume of 10.0L. If I increase the volume to 15.0L, what is my new temperature?

Answer 1

Step 1

Charles' law states that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature if the pressure remains constant.

Mathematically:

`(V1)/(T1)=(V2)/(T2)`

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Step 2

Information provided:

V1 = volume 1 = 10.0 L

T1 = temperature 1 = 298 K

V2 = volume 2 = 15.0 L

T2 = temperature 2 = unknown

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Step 3

Procedure:

`\begin{gathered} (V1)/(T1)=(V2)/(T2) \\ T2=(V2)/(V1)xT1 \\ T2=\frac{15.0\text{ }L}{10.0\text{ }L}x298K=447K \end{gathered}`

Answer: T2 = 447 K