Given the inequality;
![(x+1)(x+3)\ge0](https://img.qammunity.org/2023/formulas/mathematics/college/pb4f4rj8mqqcdtwijvmprchj5sy5kzuopz.png)
We can begin by finding the signs of the factors;
![\begin{gathered} \text{For (x+1);} \\ x+1=0\Rightarrow x=-1 \\ x+1<0\Rightarrow x<-1 \\ x+1>0\Rightarrow x>-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/94n8wfaf2rqtlcn43ctubklscggqr014f6.png)
![\begin{gathered} \text{For (x+3);} \\ x+3=0\Rightarrow x=-3 \\ x+3>0\Rightarrow x>-3 \\ x+3<0\Rightarrow x<-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hre28xfvfyesc3k655crpca8gb04avx95k.png)
We can now identify the intervals that satisfy the required condition "greater than or equal to zero."
![\begin{gathered} x<-3\text{ OR x}=-3 \\ x=-1\text{ OR x}>-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ch6rxkewaba1np2rzzysq15n3qp41e06pe.png)
This on the number line would now look like;
ANSWER:
![\begin{gathered} x\le-3 \\ OR \\ x\ge-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ujyqe702nps16o00uh2fuf3fy3s7vd4q4y.png)
Expressing the number;
![x\le-3](https://img.qammunity.org/2023/formulas/mathematics/college/kka3r2sziig3n5ijwb3f99vyhich3g7zhl.png)
in set notation;
![\mleft\lbrace x\in Z\mright|x\le-3\}](https://img.qammunity.org/2023/formulas/mathematics/college/76iczmaitr12mpjdq7umdnfxwqh28sv5a1.png)
This means;
"x is a member of the set of integers such that x is less than or equla to negative 3."
The symbol that looks like an "E" means is a member of, the one that looks like a capital Z means set of integers, the slash means "such that...".
We would not use natural numbers because negatives do not occur naturally.