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Solve your answers using inequalities using a number line strategy or a factor table strategy. Express your answers using set notation. (x+1)(x+3) ≥ 0

User Coyo
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Given the inequality;


(x+1)(x+3)\ge0

We can begin by finding the signs of the factors;


\begin{gathered} \text{For (x+1);} \\ x+1=0\Rightarrow x=-1 \\ x+1<0\Rightarrow x<-1 \\ x+1>0\Rightarrow x>-1 \end{gathered}
\begin{gathered} \text{For (x+3);} \\ x+3=0\Rightarrow x=-3 \\ x+3>0\Rightarrow x>-3 \\ x+3<0\Rightarrow x<-3 \end{gathered}

We can now identify the intervals that satisfy the required condition "greater than or equal to zero."


\begin{gathered} x<-3\text{ OR x}=-3 \\ x=-1\text{ OR x}>-1 \end{gathered}

This on the number line would now look like;

ANSWER:


\begin{gathered} x\le-3 \\ OR \\ x\ge-1 \end{gathered}

Expressing the number;


x\le-3

in set notation;


\mleft\lbrace x\in Z\mright|x\le-3\}

This means;

"x is a member of the set of integers such that x is less than or equla to negative 3."

The symbol that looks like an "E" means is a member of, the one that looks like a capital Z means set of integers, the slash means "such that...".

We would not use natural numbers because negatives do not occur naturally.

Solve your answers using inequalities using a number line strategy or a factor table-example-1
User Lgwest
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