For letter A, we see that the spinner is divided in t o7 equal parts so each part is equal to 1/7.
P(Purple) = 1/7
P(Red or Yellow) = 1/7 + 1/7 = 2/7 because either red or yellow will do.
P(Not green) = 1 - 1/7 = 6/7 because all other colors except green are included.
In this case, P(Not orange or pink) = (1 - 1/7) + 1/7 - 1/7 = 6/7.
First I removed orange from the options (1 - 17), then I added the probability of getting pink (1/7), minus their intersection (Not orange AND at the same time pink = 1/7).
If we take P(Not orange or pink) to mean that it can be any color but orange, or it can be pink, then we take the probability that it's not orange first. That's 1 - 1/7 or 6/7.
Next, we get the probability that the result is pink. That's 1/7.
An "OR" statement means that we need to add their probabilities and then subtract their intersection so that we don't count the intersection twice. Their intersection is when the color is not orange (yellow, green, etc.) and at the same time, it is pink. That leaves us with pink, whose probability is 1/7.
So the answer is P(Not orange or pink) = 6/7 + 1/7 - 1/7 = 6/7.
For B, P(3) = 1/3 because there is only one 3 out of 6 options.
P(Not 4 or 5) = (1 - 1/6) + 1/6 - 1/6 = 5/6
P(Number < 4) = P(1) + P(2) + P(3) = 1/6 + 1/6 + 1/6 = 3/6 or 1/2
P(Number > 0) = P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1