Answer:
y = 2(x+5)²- 60
Explanation:
f(x) = ax² +bx +c, is the standard form
f(x) = a(x - h)² +k , is the vertex form where the (h, k) is the vertex
y = 2x²+20x -10 ,
factor 2 from the two terms
y = 2(x² +10x) -10,
what perfect square has x² +10x? ... x²+10x +25 = (x+5)²
y = 2(x²+10x+25 )- 50 -10,
add 25 in parenthesis to get a perfect square yet subtract 2*25 = 50 so the equation will stay the same
y = 2(x+5)²- 60,
the equation has the vertex at (-5, -60)