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In the diagram below, AB || CDandBO - CO. А с o A B Which reason justifies that AAOB – ADOC? (G.6)(1 point) A. Hypotenuse-Leg B. Side-Side-Side OC. Angle-Side-Angle O D. Side-Angle-Side

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Problem

Solution

for this case we can see that

AB = DC

And we have also that

BO= CO

We also can see that:

< AOB = < COD

And the best answer for this case is:

B. side- side -side

In the diagram below, AB || CDandBO - CO. А с o A B Which reason justifies that AAOB-example-1
User Binish
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