The magnetic force between two current-carrying wires of length L and separated by a distance of d is expressed as
F = μoI1I2L/2πd
where
μo is the permeability of free space = 4π x 10^- 7
d is the distance apart
I1 and I2 are th current
F is the magnetic force
L is the length of the wire
From the information given,
I1 = 800
I2 = 950
L = 30
By substituting these values into the formula,
F = (4π x 10^- 7)(800)(950)(30)/2π(0.1888)
F =
The d = 0.188magnitude of the magneticforce bet is ween them