Question

A 1kg toy marshmallow launcher is initially at rest on a horizontal surface when it launches a 0.05 kg marshmallow with a velocity of 10 m/s at an angle of 60° above the horizontal. What is the speed of the launcher immediately after the marshmallow is released? Friction is negligible.Question 4 options:0.87 m/s0.35 m/s0.43 m/s0.25 m/s0.50 m/s0.10 m/s

Answer 1

Given data:

The mass of marshmallow launcher toy is M=1 kg.

The mass of marshmallow is m=0.05 kg.

The angle with horizontal is θ=60°.

The speed of marshmallow is v=10 m/s.

Considering the velocity of marshmallow is u.

Applying the conservation of momentum between the marshmallow and toy,

`\begin{gathered} Mu=mvcos\theta \\ (1)u=(0.05)(10)cos60\degree \\ u=0.25\text{ m/s} \end{gathered}`

Thus, the velocity of marshmallow is 0.25 m/s.