Question

Find the acceleration produced by a total force of 98 N on a mass of 2.0 kg. (neglect friction)

Answer 1

`49\text{ }(m)/(s^2)`

Step-by-step explanation

Newton's second law states that If a body has a net force acting on it, it is accelerated in accordance with the equation.

`\begin{gathered} F=\text{ ma} \\ \text{where F is the force} \\ m\text{ is the mass} \\ a\text{ is the acceleration} \end{gathered}`

then

Let

`\begin{gathered} F=98\text{ N} \\ m=2.0\text{ Kg} \\ a=\text{unknown}=a \end{gathered}`

now, replac3e in the expression and solve for a

`\begin{gathered} F=ma \\ 98\text{ N=2.0 Kg}\cdot a \end{gathered}`

to solve for a , divide both sides by 2.0 Kg

`\begin{gathered} 98\text{ N=2.0 Kg}\cdot a \\ \frac{98\text{ N}}{\text{2.0 Kg}}\text{=}\frac{\text{2.0 Kg}\cdot a}{\text{2.0 Kg}} \\ 49\text{ }(m)/(s^2)=a \end{gathered}`

therefore,the answer is

`49\text{ }(m)/(s^2)`

I hope this helps you