Question

How does the mean absolute deviation (MAD) of the data in set 1. compare to the mean absolute deviation of the data inSet 1: 12, 8, 10, 50Set 2: 13, 9, 8 A- The MAD of set 1 is 13 less than the MAD of set 2B- The MAD of set 1 is 13 more than the MAD of set 2C- The MAD of set 1 is 2 more than the MAD of set 2D- The MAD of set 1 is 2 less than the MAD of set 2

Answer 1

The Mean Absolute Deviation is:

`\begin{gathered} \text{MAD}=(1)/(N)\sum ^N_(i\mathop=1)\mleft|x_i-\bar{x}\mright| \\ \text{where }\bar{\text{x}}\text{ is the mean} \end{gathered}`

For set1:

For set2:

So the option B is the correct answer. MAD1 is 13 more than MAD2