In quadrant 4, we need to graph a reference right triangle:
Where cosθ= adjacent side/ hypotenuse . Therefore, 2 is the value for the adjacent side and the hypotenuse is equal to 7.
Now, to find the opposite side, we need to use the Pythagorean theorem:

Where c represents the hypotheses,
a represents the adjacent side and b represents the opposite side.
Solve the equation for b, then:
![b=\sqrt[]{c^2-a^2}](https://img.qammunity.org/2023/formulas/mathematics/college/ptc2ov1yruy0vp8p546hyspawqc9i45oxd.png)
Replacing the values:
![b=\sqrt[]{(7)^2-(2)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/df3i2su8j2dp1p2qp1zkwcx4xwo95xpwd2.png)
Hence:
![b=3\sqrt[]{5}](https://img.qammunity.org/2023/formulas/mathematics/college/62ra04zkmc2ncl5vubp7cjbd3dkgbj7jzf.png)
Finally, we have that sin(theta)= opposite side / hypotenuse.
Replacing with the values, therefore:
![\sin \theta=\frac{3\sqrt[]{5}}{7}](https://img.qammunity.org/2023/formulas/mathematics/college/7kxm49s6gbs1bhkw7rcovc1d69dwob90rf.png)