Question

Find the equation of the given line.Find the equation of the line passing through (3, 6) and (5, 7).y=

Answer 1

`\begin{gathered} m=(y2-y1)/(x2-x1) \\ m=(7-6)/(5-3) \\ m=(1)/(2) \\ \\ y=(1)/(2)x+b \\ \\ 6=(1)/(2)(3)+b \\ \\ 6=(3)/(2)+b \\ \\ 6-(3)/(2)=b \\ \\ (12)/(2)-(3)/(2)=b \\ \\ (9)/(2)=b \\ \\ y=(1)/(2)x+(9)/(2) \end{gathered}`