Question

Anyone have any idea? i dont have any idea

Answer 1

nope, sorry

Explanation:

Answer 2

`\tt f(x)=2x^2+20x-10`

let y=f(x)

`\tt y=2x^2+20x-10`

`\tt 2x^2+10x=y+10`

`\tt x^2+10x=(1)/(2) y+5`

`\tt x^2+10x+25=(1)/(2) y+30`

`\tt (x+5)^2=(1)/(2) (y+60)`

`\tt 2(x+5)^2=f(x)+60`

`\boxed{\tt f(x)=2(x+5)^2-60}`

Hope it helps! :)