Question

I need help on question 4 The value of time is 11 second.

Answer 1

Given data:

* The initial velocity given is 27.3 m/s.

* The final velocity given is 46.4 m/s.

* The value of time given is 11 second.

Solution:

The change in velocity is,

`\begin{gathered} \Delta v=v_f-v_i_{} \\ \Delta v=46.4-27.3 \\ \Delta v=19.1ms^(-1) \end{gathered}`

Thus, the value of acceleration is,

`a=(\Delta v)/(t)`

Substituting the known values,

`\begin{gathered} a=(19.1)/(11) \\ a=1.74ms^(-2) \end{gathered}`

Thus, the value of acceleration is 1.74 meter per second squared.

In the table form, the final answers are,