1 Answer

AndresQ · Answer 1 · 2023-02-15T15:09:37+0000

Problem

Find the polar coordinates for the point (-8,6)..

Solution

For this case we need to find the radius given by:

$r=\sqrt[]{(-8)^2+(6)^2}=10$

Now we can find the cosine of the angle on this way:

$\cos \theta=-(8)/(10)=-0.8$

And the sine would be:

$\sin \theta=(6)/(10)=0.6$

We can find the angle with this operation:

$\theta=\cos ^(-1)(0.8)=36.87º$

And then our answer would be:

$r=10,\theta=36.87º$

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