Question

Find the polar coordinates for the point (-8,6). Please help I need an explanation because I'm lost. thank you

Answer 1

Problem

Find the polar coordinates for the point (-8,6)..

Solution

For this case we need to find the radius given by:

`r=\sqrt[]{(-8)^2+(6)^2}=10`

Now we can find the cosine of the angle on this way:

`\cos \theta=-(8)/(10)=-0.8`

And the sine would be:

`\sin \theta=(6)/(10)=0.6`

We can find the angle with this operation:

`\theta=\cos ^(-1)(0.8)=36.87º`

And then our answer would be:

`r=10,\theta=36.87º`