We are given the following sequence
![(2)/(7),(5)/(14),(3)/(7),(1)/(2),\ldots](https://img.qammunity.org/2023/formulas/mathematics/college/lyq73apblrt3wmvpw8e2yqd6p99pemdx1t.png)
Let us check if there is a common difference between the consecutive terms
![\begin{gathered} (5)/(14)-(2)/(7)=(5-2(2))/(14)=(5-4)/(14)=(1)/(14) \\ (3)/(7)-(5)/(14)=(2(3)-5)/(14)=(6-5)/(14)=(1)/(14) \\ (1)/(2)-(3)/(7)=(7(1)-2(3))/(14)=(7-6)/(14)=(1)/(14) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7ldd18tzz4jqoic9tkms8sj99u48c5bw2v.png)
As you can see, there is a common difference between the terms that is 1/14
If we add 1/14 to the last term of the sequence (1/2) then we would get the next fraction in the sequence.
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