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The sum of two numbers x and y is 12. The difference of four times the larger number and two times the smaller number is 18. What system of equations would be used

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Answer:

x+y = 12 and 4y - 2x = 18

Step-by-step explanation:

let the smaller be x

Ler the larger number be y

Taking the sum of both numbers;

x+y = 12 ... 1

four times the larger number = 4y

two times the smaller numbers = 2x

If the difference is 18, then;

4y - 2x = 18 ...2

The required system of equations are;

x+y = 12 and 4y - 2x = 18

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