Question

Solve the system by substitution type your steps.x=2y-53x-y=5

Answer 1

Given:

x = 2y - 5................................................1

3x - y = 5.................................................2

Using substitution method, substitute (2y - 5) for x in equation 2:

3(2y - 5) - y = 5

Expand the parenthesis using distributive property:

3(2y) - 3(5) - y = 5

6y - 15 - y = 5

6y - y - 15 = 5

5y - 15 = 5

Add 15 to both sides:

5y - 15 + 15 = 5 + 15

5y = 20

Divide both sides by 5:

`\begin{gathered} (5y)/(5)=(20)/(5) \\ \\ y=4 \end{gathered}`

Substitiute 4 for y in equation 1:

x = 2y - 5

x = 2(4) - 5

x = 8 - 5

x = 3

Therefore, we have:

x = 3, y = 4

ANSWER:

x = 3 and y = 4