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Suppose an object starts from rest and achieves an operating speed of 33,500 rev/min. If it requires 1.6 s for the tool to reach operating speed and it is held at that speed for 50.0 s, how many rotations has the bit made? Suppose it requires another 10.0 s for the tool to return to rest. (Express your answer to two significant figures.)1. How many rotations does the tool complete from rest to finish?

1 Answer

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From the information given, the object starts from rest. This means that

initial angular velocity, wo = 0

It achieves an angular speed of 33,500 rev/min. This means that

final angular velocity, wf = 33,500 rev/min

We would convert 33,500 rev/min to rev/s by dividing by 60. It becomes

558.33 rev/s

time required = 1.6

We would calculate the angular displacement, θ during this period this period by applying the formula,

θ = 1/2(wo + wf)t

θ = 1/2(0 + 558.33)1.6

θ = 446.664 rev

The object continued at this speed for 50s. This means that the angular acceleration is zero since the speed was constant. During this period,

wo = 558.33 rev/s

a = 0

t = 50

We would find the number of revolutions by applying the formula,

θ = wot + 1/2at^2

θ = 558.33 * 50 + 1/2 x 0 x 50^2

θ = 27916.5 rev

Total number of revolutions at this point is

446.664 + 27916.5 = 28363.16 revs

For the final part,

It returns to rest after 10 s. Thus,

t = 10

wf = 0

wo = 558.33

We would find the number of revolutions in this part by applying the formula

θ = 1/2(wo + wf)t

θ = 1/2(558.33 + 0)10

θ = 2791.65 rev

Total revolutions completed is

28363.164 + 2791.65 = 31154.81 revolutions

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