Question

Write the molecular equation and net ionic equation for the reaction of hydroiodic acid and potassium hydroxide. Include phases(states). Enter the formula for water as H,O.molecular equation:net ionic equation:

Answer 1

`\begin{gathered} \text{ Molecular equation; HI}_((aq))+\text{ KOH}_((aq))\rightarrow\text{ KI}_((aq))\text{ + H}_2O(l) \\ \\ \text{ Net ionic equation; H}_((aq))^++\text{ OH}_((aq))^-\rightarrow\text{ H}_2O(l) \end{gathered}`

Step-by-step explanation

Part A

Step 1: Write the molecular formula for both hydroiodic acid and potassium hydroxide

`\begin{gathered} \text{ Hydroiodic acid = HI} \\ \text{ Potassium hydroxide = KOH} \end{gathered}`

Step 2: Write a balanced equation between the two compounds

`\text{ HI}_((aq))\text{ + KOH}_((aq))\rightarrow\text{ KI}_((aq))\text{ + H}_2O(l)`

Hence, the molecular equation for the reaction is

`\text{ Molecular equation; HI}_((aq))\text{ + KOH}_((aq))\text{ }\rightarrow\text{ KI}_((aq))\text{ + H}_(2_)O(l)`

Part B

Write the ionic equation of the reaction in part A

To write the ionic equation of the above equation, you need to understand certain rules listed below

1. Only compounds that the exit in the aqueous state can be written in the ionic form

2. Compounds that exist in the liquid, solid, and gaseous phase can't be broken into ionic form

Step 1: write the molecular equation in the ionic form

`\text{ H}_((aq))^+\text{ + I}_((aq))^-+\text{ K}_((aq))^++\text{ OH}_((aq))^-\rightarrow\text{ K}_((aq))^++\text{ I}_((aq))^-+\text{ H}_2O(l)`

Step 2: Cancel the spectator ions

Spectator ions are those ions that are present on both sides of the equation

`\begin{gathered} \text{ H}^++\cancel{I^-}+\cancel{K^+}\text{ + OH }\rightarrow\cancel{K^+}+\cancel{I^-}+H_2O(l) \\ \\ \text{ H}_((aq))^+\text{ + OH}_((aq))^-\text{ }\rightarrow\text{ H}_2O(l)\text{ -------------- Net ionic equation} \end{gathered}`