Given data:
* The mass of the textbooks is m = 23 kg
* The displacement of the textbooks is d = 75 meters.
* The acceleration of the motion is,
![a=0.75ms^(-2)](https://img.qammunity.org/2023/formulas/physics/college/okmm2hz7m2gi4kjc0l0lerbfteljn40us9.png)
Solution:
According to Newton's second law, the force acting on the textbooks is,
![F=ma](https://img.qammunity.org/2023/formulas/physics/high-school/f29csqfwijobd1j24f6y6vv1aba7x8qmg1.png)
Substituting the known values,
![\begin{gathered} F=23*0.75 \\ F=17.25\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/so988aq6jzxg8sn26rh1teh8o8374fkb5m.png)
The work done on the textbooks is,
![\begin{gathered} W=Fd \\ W=17.25*75 \\ W=1293.75\text{ J} \\ W=1.29375*10^3\text{ J} \\ W\approx1.3\text{ kJ} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/7h9ua9q27fmgf6n5kjjd1uu1a9u8cybcst.png)
Thus, the work done on the textbooks is approximately 1.3 kJ.