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What is the second step in proving by mathematical induction that for every positive integer n, 11^n - 6 is divisible by 5, is true?

User Tosca
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Let P(n) be the statement that 11^n - 6 is divisible by 5.

BASE CASE:

Let n = 1. This gives 11^1 - 6 = 5, obviously divisible by 5, therefore we know that P(1) is true.

HYPOTHESIS STEP:

Assume that P(k) is true for some positive integer k.

We can write this a different way: 11^k – 6 = 5m where m is also a positive integer.

INDUCTION STEP:

We will now show that P(k+1) is true.

P(k+1) states that 11^k+1 – 6 is divisible by 5.

11^k+1 – 6 = 11 * (11^k) – 6

= 11* (6 + 5m) – 6 (now we use our hypothesis step, with rearranged expression 11^k = 6 + 5m)

= 55m + 60 (multiplying out the brackets gives)

= 5 * (11m + 12) (now factorising again)

Which shows that this is a factor of 5 and that P(k+1) is true.

CONCLUSION: Since P(k+1) is true given P(k), and we know that P(1) is true, we have proved by induction that P(n) is true for all positive integer n.

User Dmytro Yashchenko
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