Solution:
Let:

To get the value of x, we add the Equation 1 and 2.
13x = -21 - 6y
+ - 8x = 36 + 6y
We will get:
5x=15
Calculate:
x= 3
Since x= 3, we plug in what we know:
13x = -21 - 6y
13(3) = -21 - 6y
39 = -21 - 6y
Simplify and rearrange:
-6y = 39 + 21
-6y= 60
Calculate:
y= -10
Therefore, the values are x= 3, y= -10 or (3,-10).