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A temperature of a 0.25 kg sample of copper decreases from 75.0 °C to 25.0 °C. How much heat flows out of the copper sample?

A temperature of a 0.25 kg sample of copper decreases from 75.0 °C to 25.0 °C. How-example-1
User Dallin
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1 Answer

4 votes

ANSWER

4837.5 J

Step-by-step explanation

The heat needed to change the temperature of a sample of mass m of a substance whose specific heat is c is,


Q=m\cdot c\cdot\Delta T

Where the change in temperature ΔT is,


\Delta T=T_f-T_i

In this problem, we have a sample of copper with a mass of 0.25kg, its specific heat is 387J/(kg°C), its initial temperature is 75°C and its final temperature is 25°C. The heat for this change of temperature is,


Q=0.25\operatorname{kg}\cdot387\frac{J}{\operatorname{kg}\cdot\text{\degree}C}\cdot(25\text{\degree}C-75\text{\degree}C)=-4837.5J

The result is negative, because the heat flows out of the copper, and not in.

Hence, 4837.5J flows out of the copper sample.

User Enzojz
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